GeekZilla
Instanciating an object from it's type name
Instanciating a control from it's type name is easy..
string typeName = "YourNameSpace.YourObject"; Type assType = Type.GetType(typeName); object dynamicControl = Activator.CreateInstance(assType);
One thing you may run into is that in some cases the type name needs to be a fully qualified name.. You can get this name like so:
string typeName = this.GetType().AssemblyQualifiedName;
Author Paul Hayman
Paul is the COO of kwiboo ltd and has more than 20 years IT consultancy experience. He has consulted for a number of blue chip companies and has been exposed to the folowing sectors: Utilities, Telecommunications, Insurance, Media, Investment Banking, Leisure, Legal, CRM, Pharmaceuticals, Interactive Gaming, Mobile Communications, Online Services.
Paul is the COO and co-founder of kwiboo (http://www.kwiboo.com/) and is also the creator of GeekZilla.
