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Excellent IIS Metabase Helper
Paul Hayman (441 views)
Excellent IIS Metabase Helper
Found this : http://agramont.net/blogs/provware/default.aspx
http://agramont.net/blogs/provware/archive/2006/07/31/Provware_3A00_-Getting-Started-_2800_Build-001_2900_.aspx
Has the potential to be an excellent Metabase wrapper.
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Why we use C# for .NET development
Dave Howard (10900 views)
Why we use C# for .NET development
#$#<a href="http://www.dotnetkicks.com/kick/?url=http://www.geekzilla.co.uk/View026313AC-108F-4EA1-90A2-5E5BE0DEE0F2.htm"><img src="http://www.dotnetkicks.com/Services/Images/KickItImageGenerator.ashx?url=http://www.geekzilla.co.uk/View026313AC-108F-4EA1-90A2-5E
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Bug in VS2005? Using Typed DataSets with SQL 2005 and stored procedures
Dave Howard (6664 views)
Bug in VS2005? Using Typed DataSets with SQL 2005 and stored procedures
#$#<a href="http://www.dotnetkicks.com/kick/?url=http://www.geekzilla.co.uk/View72C81AA0-44A5-4E2C-8903-B1EA7D7643EA.htm"><img src="http://www.dotnetkicks.com/Services/Images/KickItImageGenerator.ashx?url=http://www.geekzilla
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Getting on the Vista developers merry-go-round
Mark Page (1454 views)
Getting on the Vista developers merry-go-round
Trying to keep up with the various Vista Beta releases? Want to develop but not sure which version will work on your platform?
Here's a useful set of links to make sure you get the right version of the runtime, SDK, Orcas VS extensions and WCF l
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Extending Strongly Typed Datasets
Dave Howard (3164 views)
Extending Strongly Typed Datasets
Strongly Typed Datasets are a rather nice addition to VS2005 (they don't lend themselves well to acronyms however)
You still need to create a database and tables and realationships but using STDs saves a writing huge amount of code.
If this code were gene
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Evaluating Expressions
Paul Hayman (2433 views)
Evaluating Expressions
You can evaluate sums in the fly using .net DataTables.
This is how you do it (C# 2005).
#c#string sum = "(1+2)/4";
#c#System.Data.DataTable evaluator = new System.Data.DataTable("temp");
#c#double result;
#c#
#c#result = (double)evaluator.Compute(sum, null);
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